Tweeper.php: fix Invalid Character Error when converting Instagram json to XML

[tweeper.git] / src / rss_converter_facebook.com.xsl

diff --git a/src/rss_converter_facebook.com.xsl b/src/rss_converter_facebook.com.xsl
index 283549c..7ead3ef 100644 (file)
--- a/src/rss_converter_facebook.com.xsl
+++ b/src/rss_converter_facebook.com.xsl
@@ -1,7 +1,7 @@
 <!--
   Stylesheet to convert a Facebook public page to RSS.
 
-  Copyright (C) 2015  Antonio Ospite <ao2@ao2.it>
+  Copyright (C) 2015-2018  Antonio Ospite <ao2@ao2.it>
 
   This file is part of tweeper.
 
@@ -33,7 +33,6 @@
 <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
     xmlns:php="http://php.net/xsl"
-    xsl:extension-element-prefixes="php"
     exclude-result-prefixes="php">
 
     <xsl:output method="xml" indent="yes"/>
@@ -106,8 +105,8 @@
 
     <xsl:template match="/">
         <xsl:variable name="channel-title" select="//title"/>
-        <xsl:variable name="channel-link" select="//div[contains(@class, 'fbUserStory') or contains(@class, 'userContentWrapper')][1]//a[1]/@href"/>
-        <xsl:variable name="channel-image" select="//div[contains(@class, 'fbUserStory') or contains(@class, 'userContentWrapper')][1]//a[1]//img/@src"/>
+        <xsl:variable name="channel-link" select="//meta[@property='og:url']/@content"/>
+        <xsl:variable name="channel-image" select="//meta[@property='og:image']/@content"/>
 
         <rss version="2.0">
             <xsl:attribute name="xml:base"><xsl:value-of select="$BaseURL" /></xsl:attribute>
@@ -121,7 +120,7 @@
                 </link>
                 <description>
                     <xsl:text disable-output-escaping="yes">&lt;![CDATA[</xsl:text>
-                    <xsl:copy-of select="//div[@data-id='1']/node()"/>
+                    <xsl:value-of select="//meta[@property='og:description']/@content"/>
                     <xsl:text disable-output-escaping="yes">]]&gt;</xsl:text>
                 </description>
                 <image>