rss_converter_instagram.com.xsl: don't use a template for the enclosure
authorAntonio Ospite <ao2@ao2.it>
Fri, 20 May 2016 16:17:59 +0000 (18:17 +0200)
committerAntonio Ospite <ao2@ao2.it>
Fri, 20 May 2016 16:23:34 +0000 (18:23 +0200)
Each post has exactly one image, it is enough to copy the generated
element in-place without applying templates.

rss_converter_instagram.com.xsl

index 633c8ef..54f660e 100644 (file)
         <xsl:text>https://instagram.com</xsl:text>
     </xsl:variable>
 
-    <xsl:template match="display_src">
-        <xsl:copy-of select="php:function('Tweeper::generateEnclosure', string(text()))"/>
-    </xsl:template>
-
     <xsl:variable name="user-name" select="//ProfilePage/user/username"/>
 
     <!-- Some users do not specify the full name -->
@@ -93,7 +89,7 @@
                 <xsl:text disable-output-escaping="yes">]]&gt;</xsl:text>
             </description>
             <xsl:if test="$generate-enclosure = 1">
-                <xsl:apply-templates select="./display_src"/>
+                <xsl:copy-of select="php:function('Tweeper::generateEnclosure', string($item-content-image))"/>
             </xsl:if>
         </item>
     </xsl:template>