rss_converter_instagram.com.xsl: show the user name in the titles
authorAntonio Ospite <ao2@ao2.it>
Wed, 29 Jul 2015 21:05:47 +0000 (23:05 +0200)
committerAntonio Ospite <ao2@ao2.it>
Wed, 29 Jul 2015 21:05:47 +0000 (23:05 +0200)
This makes it easier to see who created the item when different
Instagram feeds are grouped into a directory.

rss_converter_instagram.com.xsl

index 4f1d14f..bf83dde 100644 (file)
         <item>
             <title>
                 <xsl:variable name="title-length" select="140"/>
+                <xsl:variable name="item-content-title" select="normalize-space(concat($user-name, ': ', $item-content-caption))"/>
                 <!-- ellipsize, inspired from http://stackoverflow.com/questions/13622338 -->
                 <xsl:choose>
-                    <xsl:when test="string-length($item-content-caption) > $title-length">
+                    <xsl:when test="string-length($item-content-title) > $title-length">
                         <xsl:variable name="truncated-length" select="$title-length - 3"/>
-                        <xsl:value-of select="normalize-space(substring($item-content-caption, 1, $truncated-length))"/>
+                        <xsl:value-of select="substring($item-content-title, 1, $truncated-length)"/>
                         <xsl:text>...</xsl:text>
                     </xsl:when>
                     <xsl:otherwise>
-                        <xsl:value-of select="normalize-space($item-content-caption)"/>
+                        <xsl:value-of select="$item-content-title"/>
                     </xsl:otherwise>
                 </xsl:choose>
             </title>