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rss_converter_instagram.com.xsl: fix the channel link
author
Antonio Ospite <ao2@ao2.it>
Fri, 20 May 2016 16:00:50 +0000
(18:00 +0200)
committer
Antonio Ospite <ao2@ao2.it>
Fri, 20 May 2016 16:00:50 +0000
(18:00 +0200)
rss_converter_instagram.com.xsl
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diff --git
a/rss_converter_instagram.com.xsl
b/rss_converter_instagram.com.xsl
index
f12ecbb
..
97d39d2
100644
(file)
--- a/
rss_converter_instagram.com.xsl
+++ b/
rss_converter_instagram.com.xsl
@@
-100,7
+100,7
@@
<xsl:template match="/">
<xsl:variable name="channel-title" select="concat('Instagram / ', $screen-name)"/>
<xsl:template match="/">
<xsl:variable name="channel-title" select="concat('Instagram / ', $screen-name)"/>
- <xsl:variable name="channel-link" select="concat($BaseURL,
//__path
)"/>
+ <xsl:variable name="channel-link" select="concat($BaseURL,
'/', $user-name
)"/>
<rss version="2.0">
<xsl:attribute name="xml:base"><xsl:value-of select="$BaseURL" /></xsl:attribute>
<rss version="2.0">
<xsl:attribute name="xml:base"><xsl:value-of select="$BaseURL" /></xsl:attribute>